Question

Write the equation 5x-2/2-19x+6/2x=3x-2/4 in general quadratic form. 7x 210x 2 - 39x - 10 = 0 7x 2 - 40x - 12 = 0 7x 2 - 40x + 6 = 0

Answer 1

7x-40x-12=0

Explanation:

I know because I got it wrong following on of the other mentally disabled individuals who posted an innacurate answer here. Your welcome for an accurate answer from a semi intelligent individual. : )

Answer 2

`7x^2 - 40x + 12 = 0`

Explanation:

The equation
`(5x-2)/(2)-(19x-6)/(2x)=(3x-2)/(4)` can be written as a quadratic with the following steps:

1. Multiply each term by 4x to clear all denominators.
2. Apply the distributive property.
3. Combine like terms.
4. Move all terms to one side.

Step 1 :

`(5x-2)/(2)-(19x-6)/(2x)=(3x-2)/(4)\\4x((5x-2)/(2)-(19x-6)/(2x)=(3x-2)/(4))\\2x(5x-2) -2(19x-6) = x(3x-2)`

Step 2:

`2x(5x-2) -2(19x-6) = x(3x-2)\\10x^2 - 4x - 38x + 12 = 3x^2 - 2x`

Step 3:

`10x^2 - 4x - 38x + 12 = 3x^2 - 2x\\10x^2 - 42x + 12 = 3x^2 - 2x`

Step 4:

`10x^2 - 42x + 12 = 3x^2 - 2x\\7x^2 - 40x + 12 = 0`