Question

Obtain all zeros of x^4-7x^2+12, if two numbers of its zeros are √3 and -√3

Answer 1

Explanation:

x^2=u

u^2-7u+12=0

(u-3)(u-4)=0

u=3,4

x^2=3,4

x^2=3

x = ±√3

x^2 = 4

x=±2