398,240 views
42 votes
42 votes
NO LINKS!! Please help me with this problem​

NO LINKS!! Please help me with this problem​-example-1
User MarkE
by
2.9k points

1 Answer

28 votes
28 votes

Answer:

y²/324 -x²/36 = 1

Explanation:

Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...

y²/b² -x²/a² = 1

Application

Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...

b = 18

b/a = 3 ⇒ a = 18/3 = 6

The equation of the hyperbola in standard form is ...

y²/324 -x²/36 = 1

NO LINKS!! Please help me with this problem​-example-1
User Nozim Turakulov
by
3.0k points