Question

find the area of a regular hexagon with a radius of 8 and an apothem of 4 squareroot 3. round your answer to the nearest tenth.

Answer 1

The area of the regular hexagon is 166.3 units^{2}

Explanation:

we know that

The area of a regular hexagon is equal to the area of six equilateral triangles

so

The area of a regular hexagon is

A=6[(1/2)bh]

The length side of the regular hexagon is equal to the radius

b=8 units

h=4\sqrt{3} units -----> the apothem

substitute the values

A=6[(1/2)(8)(4\sqrt{3})]=166.3 units^{2}