Question

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

Answer 1

`\bf{Hey\ there!}`

`\bf{Quadratic\ formula\ is:}`
`\bf{x=(-b\pm√(b^2-4ac))/(2a)} \ or \ you\ could\ say\ ax^2+bx+c=0`

`\bf{\bullet\ First: subtract\ by\ 2x\ on\ your\ sides\ that\ you're\ working\ with}`

`\bf{Like:x^2+20-2x=2x-2x}`

`\bf{We\ get:x^2-2x+20=0}`

`\bf{\bullet \ a=1}\\ \bf{\bullet \ b=-2}\\ \bf{\bullet \ c=20}`

`\bf{x=(-(-2)\pm√((-2)^2-4(1)(20)))/(2(1))`

`\bf{(-2)^2-4(1)(20)=-76} \\ \\ \bf{2(1)=2}`

`\bold{-(-2)=-1(-2))=+2}`

`\bf{x=(2\pm√(-76))/(2)}`

`\bf{Thus\ there\ is\ NO\ REAL\ SOLUTIONS}`

`\text{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}`

`\frak{LoveYourselfFirst:)}`