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Solve for x in the given interval.

sec x= -2√3/3, for π/2 ≤x≤π

Solve for x in the given interval. sec x= -2√3/3, for π/2 ≤x≤π-example-1
User Weivall
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2 Answers

7 votes

Answer:

Answer B.

Explanation:

5pi/6

User Jakub Kukul
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4 votes

Answer:

b.
x=(5\pi)/(6)

Explanation:

The given function is


\sec x=-(2√(3) )/(3),\:\:for\:\:(\pi)/(2)\le x \le \pi

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;


(1)/(\cos x)=-(2√(3) )/(3)


\Rightarrow \cos x=-(3)/(2√(3) )


\Rightarrow \cos x=-(√(3))/(2)

We take the inverse cosine of both sides to obtain;


x=\cos^(-1)(-(√(3))/(2))


x=(5\pi)/(6)

User Janique
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5.6k points