Question

Plz help me with this

Answer 1

Answer:
`\bold{c)\quad (2(2x+7))/((x-4)(x+2))}`

Explanation:

`(x^2+3x+2)/(x^2-2x-8)-(x^2-x-12)/(x^2-2x-8)\\\\\\\text{They already have a common denominator so just add the numerators.}\\\text{Distribute the negative sign to the fraction on the right side and factor}\\\text{the denominator.}\\\\(x^2+3x+2-x^2+x+12)/((x-4)(x+2))=(4x+14)/((x-4)(x+2))=(2(2x+7))/((x-4)(x+2))`