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Equation for hyperbola shown

Equation for hyperbola shown-example-1
User Suni
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2 Answers

7 votes

Answer:

CORRECT ANSWER IS A

Explanation:

User Wurli
by
8.0k points
3 votes

Answer:

The equation of the hyperbola is x²/60² - y²/11² = 1 ⇒ 1st answer

Explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with

center (0 , 0) and transverse axis parallel to the x-axis is

x²/a² - y²/b² = 1

* Where:

# the length of the transverse axis is 2a

# the coordinates of the vertices are (±a , 0)

# the length of the conjugate axis is 2b

# the coordinates of the co-vertices are (0 , ±b)

* Now from the graph

- The center of the hyperbola is (0 , 0)

- The vertices of the hyperbola are (-60 , 0) and (60 , 0)

∴ a = ± 60

∴ a² = 60²

- The co-vertices of the hyperbola are (0 , -11) and (0 , 11)

∴ b = ± 11

∴ b² = 11²

* Substitute the values of a² and b² in the form of the equation

∴ x²/60² - y²/11² = 1

* The equation of the hyperbola is x²/60² - y²/11² = 1

User Christophe Keller
by
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