Question

1. Calculate the force between charges of 0.000569 C and 0.00000186 C, if they are 0.5 m apart.

Answer 1

38.1 N

Step-by-step explanation:

The electrostatic force between two charged objects is given by:

`F=k(q_1 q_2)/(r^2)`

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two objects

In this problem, we have

`q_1 = 0.000569 C\\q_2 = 0.00000186 C\\r = 0.5 m`

so, the electrostatic force is

`F=(9\cdot 10^9 Nm^2 C^(-2))((0.000569 C)(0.00000186 C))/((0.5 m)^2)=38.1 N`