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Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 66 kmh faster than the other. If the two planes are 10,716 kilometers apart after 6 hours, what is the rate of each plane

User Harny Otuoniyo
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1 Answer

23 votes
23 votes

Answer:

  • The rate of planes: 926 km/h and 860 km/h

=========================

Given

  • Two planes travel in opposite directions,
  • One plane travels 66 km/h faster than the other,
  • The distance between the two planes after 6 hours is 10716 km.

To find

  • The rate of of each plane

Solution

The distance traveled by two planes in an hour is:

  • 10716/6 = 1786 km/h

Let the rate of one plane be x, then the other plane's rate is x - 66.

The sum of two rates is the distance traveled in one hour:

  • x + x - 66 = 1786
  • 2x - 66 = 1786
  • 2x = 1786 + 66
  • 2x = 1852
  • x = 1852/2
  • x = 926

So the rate of one plane is 926 km/h and of the other plane is:

  • 926 - 66 = 860 km/h
User Brutella
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