Question

How many grams of magnesium are required to react with 0.350 mol hydrochloric acid

Answer 1

4.253 g.

Step-by-step explanation:

• Mg reacts with HCl according to the balanced equation:

Mg + 2HCl → MgCl₂ + H₂.

It is clear that 1.0 mol of Mg reacts with 2.0 moles of HCl with a ratio of (1: 2).

∴ no. of moles of Mg that reacts with 0.35 mol of HCl = (0.35 mol)/2 = 0.175 mol.

∴ no. of grams of Mg = no. of moles x atomic mass = (0.175 mol)(24.3 mol) = 4.253 g.