Question

A cannonball is launched from the top of a 125-meter high cliff with an initial horizontal speed of 20 m/s. The (x, y) coordinate position of the launch location is designated as the (0, 0) position. Determine the (x, y) coordinate positions of the cannonball at 1-second intervals during its path to the ground. Assume g = ~10 m/s2 , down. (can print out this picture or can copy/paste in paint and add the cannonballs position to it)

Answer 1

(20 , -5)

Step-by-step explanation:

Given in the question.

initial horizontal speed
`u_(h)` = 20m/s

g = -10m/s²

y = u
`_(v)`t + 0.5 • g • t²

(equation for vertical displacement for a horizontally launched projectile)

x = u
`_(h)` • t

(equation for horizontal displacement for a horizontally launched projectile)

Plug values in the equations

y = 0(1) + 0.5(-10)(1)²

y = -5m

Here there is no initial vertical velocity (i.e., a case of a horizontally launched projectile).

x = 20 • (1)

x= 20 m

Since there is no horizontal acceleration, the horizontal distance traveled by the projectile each second is a constant value.