Question

The mean of six numbers is 45. Four of the numbers are 40, 38, 46, and 51. If the remaining two numbers are I. The ratio of 2:3, find the two numbers.

Answer 1

The numbers are 38 and 57

Explanation:

Let

x-----> the missing smaller number

y----> the missing larger number

we know that

`45=(40+38+46+51+x+y)/(6) \\ \\270=175+x+y`

`x+y= 95` -----> equation A

`(x)/(y)=(2)/(3)`

`x=(2)/(3)y` -----> equation B

substitute equation B in equation A and solve for y

`(2)/(3)y+y= 95`

`(5)/(3)y= 95`

`y=95*3/5=57`

Find the value of x

`x=(2)/(3)(57)=38`