Hello!
The answer is:
Myrna can decorate
dozens of cookies in
hours.
Why?
To solve this problem, we need to remember how to multiply mixed numbers, we can do it by the following way:
- Covert the mixed numbers to improper fractions
- Multiply the improper fractions
- Convert the result to mixed number again.
Also, we need to pay attetion to the given rate about Myrna's work.
So,
![Rate=(3(1)/(4)dozen)/(hour)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xo4o7c13set5vd6ho0lsf5zfolll16zfzg.png)
Then, to calculate how many dozen of cookies can Myrna decorate in 2 and 1/3 hours, we need to write the following equation:
![Work=Rate*Time](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aim2vdc15e3bwf2c10tbmax4rai9t89a40.png)
We already know the Myrna's rate, so substituting it into the equation to know how many dozen of cookies she can decorate in 2 and 1/3 hours, we have:
![Work=(3(1)/(4))(dozen)/(hour) *(2(1)/(3))hour](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e5sky5slk54sfy712h06e44ng19v55usz8.png)
Now, multiplying the mixed numbers we have:
- First, converting to improper fractions:
![(3(1)/(4))=3+(1)/(4)=(12+1)/(4)=(13)/(4)\\\\(2(1)/(3))=2+(1)/(3)=(6+1)/(3)=(7)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ty4nt7jrmdoq9x9v38oz5thu3sftvfrosz.png)
- Second, multiplying the fractions:
![((13)/(4))*((7)/(3))=(13*7)/(7*3)=(91)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xvtiihpmvdb9kgzo1k2vlffxzbpu4nbbgo.png)
- Converting back to mixed number:
![(91)/(12)=7.58=7(7)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yrjvum0iol54v2g8iobmszykv704vm6f15.png)
So, the answer is:
Myrna can decorate
dozens of cookies in
hours.
Have a nice day!