Question

What is the missing constant term in the perfect square that starts with x^2 - 16x ?

Answer 1

64 pleb

Explanation:

Answer 2

The missing constant term is 64

EXPLANATION

The given expression is

`{x}^(2) - 16x`

Let the k be the constant term, then

`{x}^(2) - 16x + k`

is a perfect square.

This implies that, the discriminant is zero.

The discriminant is

`D= {b}^(2) - 4ac`

`{( - 16)}^(2) - 4(1)(k) = 0`

`256 - 4k = 0`

`- 4k = - 256`

`k = ( - 256)/( - 4)`

`k = 64`