Answer:
(C) 270
Explanation:
Given: In the circle P, ∠TPB=90° and ∠TPC=128°.
To find: mTCB in circle P.
Solution: It is given that In the circle P, ∠TPB=90° and ∠TPC=128°, then
(sum of the minor and the major arc is 360°)
⇒
![90^(\circ)+mTCB=360^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9hnn8njybvtn112vlbue7xzbn0fes81827.png)
⇒
![mTCB=360-90](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qfd4t59c1lmq38nn9y93vep3x9n5tmw7z6.png)
⇒
![mTCB=270^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zfn137hh61dklyuclbzxnvionurtpfe7kv.png)
Thus, the measure of arcTCB is 270°, hence option C is correct.