Question

PLZ ANSWER RIGHT, POINTS 99!!

Select the correct answer from each drop-down menu.

Consider the following equation.


`0 = x^(2) - 10x - 27`

Complete each statement about the solutions to the equation.

The negative solution is between (Q1)__ and (Q2)__.

Q1.) A. -13

B. -3

C. -2

D. -12


Q2) A. -1

B. -11

C. -12

D. -2

________________________________________________

The positive solution is between (Q3)__ and (Q4)__.

Q3.) A. 11

B. 1

C. 2

D. 12


Q4.) A. 13

B. 3

C. 12

D. 2

Answer 1

Using the quadratic formula -b +/-√b^2-4(ac) / 2a solve for x:

10 +/-√(-10)^2 -4(1*27) / 2*1

x = 5 +/-2√13

x = -2.21

or x = 12.21

The negative solution is between -2 and -3.

The positive solution is between 12 and 13.