Answer:
The surface area of the triangular prism is
![420\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5ve5why8tlq5vl9ggc1e9gvxb3rnuiji2y.png)
Explanation:
we know that
The surface area of the triangular prism is equal to
![SA=2B+PL](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6gudw6m8t4qhsr0dxamk3klgaijxkrb583.png)
where
B is the area of the triangular base
P is the perimeter of the triangular base
L is the length of the triangular prism
Find the area of the base B
![B=(1)/(2)(16)(6)=48\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e7xizi3t3k660678fmux2qnrtacc8y1fuy.png)
Find the perimeter of the base P
![P=16+10+10=36\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e5d2slk1kcwwlcl51jyuntnuiiyw0ig7yu.png)
we have
![L=9\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fo6py9uryrl4quippp86vg9i4lsyyt6us5.png)
substitute the values
![SA=2(48)+(36)*9=420\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rpp1rp10okiaqwaj7fm7wnat5ueepc9j9v.png)