Question

Given circle assume that AB Is tangent to the circle and AD Passes through the center of the circle. If the circle has a radius of 5CM and AB is 6CM what is the length of the secant

Answer 1

d. 2√34 cm

Explanation:

Secant BD is the hypotenuse of right triangle ABD with legs given as AB = 6 cm and AD = 10 cm. Hence the Pythagorean theorem can be used to find BD:

BD = √(AB² +AD²) = √((6 cm)² +(10 cm)² = √136 cm = 2√34 cm