Question

If the voltage impressed across a circuit is held constant while the resistance is halved, what change occur?

Answer 1

The current doubles

Step-by-step explanation:

In a circuit, Ohm's law gives the relationship between voltage, current and resistance:

`V=RI`

where

V is the voltage

R is the resistance

I is the current

In this problem,

V is held constant

R is halved:
`R'=(R)/(2)`

Therefore, the new current is

`I'=(V)/(R')=(V)/(R/2)=2(V)/(R)=2I`

So, the current doubles.