Question

What is the force, in units of femtoNewtons, on an electron moving at a velocity of 7.26 x 106 ms-1 perpendicularly to a magnetic field when the magnetic flux density of 0.049 T?

Answer 1

56.9 fN

Step-by-step explanation:

The force exerted on the electron is:

`F=Bqv`

where

B is the magnetic field strength

q is the electron's charged

v is the speed of the electron

In our problem,

B = 0.049 T

`q=1.6\cdot 10^(-19) C`

`v=7.26\cdot 10^6 m/s`

Therefore, the force is

`F=(0.049 T)(1.6\cdot 10^(-19) C)(7.26\cdot 10^6 m/s)=5.69\cdot 10^(-14) N=56.9 fN`