Question

What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?​

Answer 1

`1^(f) =187.7 (J)/(kg)`

Step-by-step explanation:

SO in order to calculate the specific latent heat of fusion, you need to remember the formula:

`1^(f) =(Q)/(m)`

Where
`1^(f)` representes the specific latent heart of fusion.

`Q` represents the heat energy added, usually represented in kJ

`m` represents the mass of the object, in kg.

Now that we have our formula we just have to put our values into the formula:

`1^(f) =(Q)/(m)`

`1^(f) =(863kJ)/(4.6kg)`

`1^(f) =187.7 (J)/(kg)`

SO our answer would be
`1^(f) =187.7 (J)/(kg)`