Question

Find sinθ if cosθ =
`(2)/(3)`

Answer 1

`sin = (√(5) )/(3)`

Explanation:

SOH CAH TOA

Where:

s = sin

c = cos

t = tan

o = opposite

a = adjacent

h = hypotenuse

cos = 2/3 where 2 is adjacent side and 3 is hypotenuse, now find opposite side using a^2 + b^2 = c^2 //c is hypotenuse side

2^2 + b^2 = 3^2

4 + b^2 = 9

b^2 = 9 - 4

b^2 = 5

b = square root (5) = 5^(1/2) //opposite side

sin = O/H

`sin = (√(5) )/(3)`

//Hope it helps.