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Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ

User MartGriff
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1 Answer

5 votes

Answer: The identity is verified. See the explanation.

Explanation:

You must keep on mind the following identities:


csc\theta=(cos\theta)/(sin\theta)\\\\csc\theta=(1)/(sin\theta)\\\\sin^2\theta+cos^2\theta=1

Therefore, by substitution, you can rewrite the identity as shown below:


1+cot^2\theta=csc^2\theta\\\\1+(cos^2\theta)/(sin^2\theta)=csc^2\theta

Simpliying, you obtain:


(sin^2\theta+cos^2\theta)/(sin^2\theta)=csc^2\theta\\\\(1)/(sin^2\theta)=csc^2\theta\\\\csc^2\theta=csc^2\theta

The identity is verified.

User Alec Gerona
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