Question

Suppose a computer technical support representative can answer calls from 8 customers in an hour. What is the probability that a customer will be on hold less than 15 minutes?

Answer 1

D edge

Explanation:

Answer 2

Option d

Explanation:

We need 2 fundamental data to solve this problem.

1.- Average number of clients attended in 1 hour.

2.- Time in which it is expected that a client will be attended.

They tell us that the average number of clients served in an hour is m = 8

They tell us to calculate the probability that the client will be seen in less than 15 minutes.

But the time t in the formula is given in hours.

Therefore we must write 15 minutes according to hours.

We know that
`1\ hour = 60 minutes`.

So:

`15\ minutes[(1\ hour)/(60\ minutes)] = 0.25\ hours`.

Now we substitute in the formula
`m = 8` and
`t = 0.25` to find P.

`P = 1 -e^(-mt)\\\\P = 1- e^(-(8)(0.25))\\\\P = 1 - e^(-2)\\\\P = 0.8646\\\\P= 86\%`