Answer:
- Answer: option A) C₆H₁₂O₆ is oxidized and O₂ is reduced
Step-by-step explanation:
1) Chemical equation:
- C₆H₁₂O₆ + 6O₂ → 6CO₂+ 6H₂O + Energy
2) Oxidation states in the reactants
a) C₆H₁₂O₆
- The oxidation state of all H atoms is +1.
- The oxidation state of all O atoms is -2
Here, you will see that the oxidation state of carbon in glucose is zero.
There are 6 atoms of C which may have different oxidation number.
You can work with a more developed formula such as:
O OH OH OH OH OH
║ | | | | |
H - C¹ - C² - C³ - C⁴ - C⁵ - C⁶ - H
| | | | |
H H H H H
- C¹ is bonded to one O, one C and one H.
∴ C¹ 's oxidation state may be determined from x + (−2) + (0) + (+1) = 0
⇒ x = + 1
- C²,C³,C⁴, and C⁵ are bonded to one OH radical, two C atoms, and one H atoms.
∴ Their oxidation states are given by:
x + (−1) + 2(0) + (+1) = 0 ⇒ x=0
- C⁶ is bonded to one OH, one C, and two H atoms.
∴ C⁶ 's oxidation state may be determined from:
x + (−1) + (0) + 2(+1) = +1 ⇒ x = −1
- The overall oxidation state of C in that molecules is the algebraic sum of all each of C atom oxidation states: +1 + 0 + 0 + 0 + 0 + (-1) = 0
b) O₂ : since it is alone, its oxidation state is zero.
3) Oxidation states in the products
c) CO₂
d) H₂O
- Oxidation state of H: + 1
4) Changes in the oxidation state
- C changed from 0 in the reactats to +4 in the products
- O changed from O in the reactants to - 2 in the products
5) Conclusion:
- Since C increased its oxidation state, it is oxidized
- Since O reduced its oxidation state, it is reduced.
- Answer: option A) C₆H₁₂O₆ is oxidized and O₂ is reduced