Answer:
![P(3)=(3)/(10)=0.3\\\\P(5)=(5)/(10)=0.5\\\\P(7)=(7)/(10)=0.7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5aztp2t3ux0hzeibkf2ilsvpiz768sgxtl.png)
Explanation:
Probability is the possibility of happening of some event .
Probability =
![(No.\,\,of\,\,outcomes)/(Total\,\,no.\,\,of\,\,outcomes)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aw2rne6z31in2fptwekyqnbwvkwmecfetj.png)
Probability distribution links each outcome of an experiment with it's probability of occurrence .
Given:
![P(x)=(x)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v595k63sjhh6yz8jzk06p0ak25mozbbqd8.png)
To find: Probability distribution for the given function for x = 3 , 5 and 7
Solution:
For x = 3 :
On putting x = 3 in function
, we get
![P(3)=(3)/(10)=0.3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3wl18jtgdo2n0gqyauvdbqlsezucwz1apx.png)
For x = 5 :
On putting x = 5 in function
, we get
![P(5)=(5)/(10)=0.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hzq7dcpitg6c0m93c7wrfh0zt70h7nsbf1.png)
For x = 7 :
On putting x = 7 in function
, we get
![P(7)=(7)/(10)=0.7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r3j2aslsspvcp70bpza6l2ztgezuk8t8r8.png)