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Determine the eccentricity, the type of conic, and the directrix for
r=6/1+2cos theta

Determine the eccentricity, the type of conic, and the directrix for r=6/1+2cos theta-example-1
User Jujka
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2 Answers

4 votes

Answer:

Choice C is correct

User Bill Kidd
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3 votes

Answer:

Choice C is correct

Explanation:

The polar equation of the conic section is in standard form. The eccentricity is simply the coefficient of cos theta; thus e = 2

The eccentricity being more than 1 implies the conic section is a hyperbola.

To determine the directrix, divide 6 by 2 to obtain 3. The conic section opens to the left thus;

directrix; x = 3

User Densil
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6.2k points