Question

If ||M and M6 = 4X - 15 and m7 = x + 30 then m 6 =​

Answer 1

15

Explanation:

∠6 and ∠7 are Alternate Interior Angles.

The lines l and m are parallel, therefore ∠6 and ∠7 are congruent.

m∠6 = m∠7 → 4x - 15 = x + 30 add 15 to both sides

4x = x + 45 subract x from both sides

3x = 45 divide both sides by 3

x = 15

Answer 2

`\angle 6 =45^(\circ)`

Explanation:

We are given that l || m

`\angle 6 = 4x-15`

`\angle 7 = x+30`

Since l || m

So,
`\angle 6 = \angle 7` (Alternate interior angles are equal )

So,
`4x-15 =  x+30`

`3x= 45`

`x= 15`

`\angle 6 = 4x-15=4(15)-15 = 45^(\circ)`

So,
`\angle 6 =45^(\circ)`