Question

Sandy mixed 9 ml of an acidic solution with 8 ml of a 42% acidic solution, to make a 45% acidic solution. Find the percent acid concentration of the first solution.

Answer 1

47.67%

Explanation:

Amount of 1st solution = 9 ml

Let the percentage acid concentration of 1st solution is x%

Amount of 2nd solution = 8 ml

Percentage acid concentration of 2nd solution = 42%

Percentage acid concentration of the mixture = 45%

Amount of the mixture = 8 + 9 = 17 ml

1st Solution + 2nd Solution = Mixture

x% of 9 ml + 42% of 8 ml = 45% of 17 ml

`0.09x + 3.36 = 7.65\\\\ 0.09x = 7.65 - 3.36\\\\ 0.09x = 4.29\\\\ x = (4.29)/(0.09)\\\\ x = 47.67`

Thus, the percent acid concentration of first solution is 47.67%