Question

If you push twice as hard against a stationary brick wall, the amount of work you do

Answer 1

Zero

Step-by-step explanation:

The work done on an object is given by:

`W=Fd cos \theta`

where

F is the force applied on the object

d is the displacement of the object

`\theta` is the angle between the direction of the force and the displacement

In this problem, you are pushing again a stationary wall: this means that the walls does not move. As a result, the displacement is zero: d=0. Therefore, the work done is also zero: W=0.