Question

(w-w^2)^4=?
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Answer 1

w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 .

Explanation:

(w - w^2)^4

= w^4 ( 1 - w)^4

By the binomial theorem:

= w^4( 1 - 4w + 6w^2 - 4w^3 + w^4)

= w^4 - 4w^5 + 6w^6 - 4w^7 + w^8

= w^8 - 4w^7 + 6w^6 - 4w^5 + w^4 ( Standard form).