Question

Find the vertex of the quadratic function.

ƒ(x) = 2(x−1)² +3
a. (1,3)
b. (2, -1)
c. (-1,3)
d. (2,3)

Answer 1

hi,

the function is given with it's canonic form.

canonic form is : f(x) = a ( x-α)² + β

α and β are the value of the coordonnates of the vertex.

so here we have : ƒ(x) = 2(x−1)² +3

with α = 1 and β = 3

so vertex is V (1;3)

So yes, answer is A.