Question

The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If m is the mean number of customers serviced in an hour, then P=1-e^mt

Answer 1

Answer: option d.

Explanation:

You have the following formul given in the problem:

`p=1-e^(-mt)`

You know that:

The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

`m=6`

As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:

`t=0.5`

Substitute the values above into the formula.

Then, you obtain:

`p=1-e^(-(6)(0.5))=0.95` or 95%