Question

If the polynomials p(x) = ax³+4x²+3x-4 and q(x) = x² - 4x + a, leave the same remainder when divided by (x-3), find value of a.

Steps pls​

Answer 1

a = -22/13.

Explanation:

By the Remainder Theorem

p(3) = remainder when p(x) is divided by x-3.

q(3) is equal to the same remainder.

So we have:

p(3) = q(3) , so

a(3)^3 + 4(3)^2 + 3(3) - 4 = 3^2 - 4(3) + a

27a + 36 + 9 - 4 = 9 - 12 + a

27a - a = 9 - 12 - 36 - 9 + 4

26a = -12 - 36 + 4

26a = -44

a = -44/26

a = -22/13.