Answer:
Option 1: 28 is the correct answer.
Explanation:
The given expression for sum is:
![\[ \sum_(n=1)^(4) {2n+2} = 1 \]](https://img.qammunity.org/2022/formulas/mathematics/college/bdwvncekekqtmnxiq9ys0xraqsbw5emc08.png)
There will be four terms in the sum
We have to find the terms by putting n=1,2,3,4 as n=1 to 4
Putting n=1

Putting n=2

Putting n=3

Putting n=4

So the summation will expand to:
![\[ \sum_(n=1)^(4) {2n+2} = 1 \] = 4+6+8+10 = 28](https://img.qammunity.org/2022/formulas/mathematics/college/9t5z83p3gu51tymd3xgtcb47bsz1jl1nk9.png)
Hence,
Option 1: 28 is the correct answer.