Question

P(A)=0.22 and P(B)=0.46
Find P(A OR B)

Answer 1

In general, the probability of a disjunction is

`P(A \lor B) = P(A)+P(B)-P(A\cap B)`

In this case, A and B are mutually exclusive, so
`P(A\cap B)=0`

This simplifies the formula to

`P(A \lor B) = P(A)+P(B) = 0.22+0.46 = 0.68`