Question

4. (06.02 MC)

Write an equation of a line that passes through the point (7,3) and is parallel to the line y =
y=-3x+3.0
x + 3. (5 points)

Answer 1

-2/3x+23/3

Explanation:

y= mx+c

where

m is the slope c is the y-intercept.

1-getting the slope:

we are given that the line we are looking for is parallel to the line

y=-2/3x+3

this means that the slope of the two lines are equal . comparing the general formula with the given line , we would find that the slope of the given lines -2/3.this means that the slope of the lines we are looking for is also -2/3

The equation of the line now becomes:y=-2/3x+c

2-getting the value of c

to get the value of c, we will use a point that belongs to the line (7,3),substitute in the equation and solve for c as follows:

y=-2/3x+c

3=(-2/3)(7)+c

3=-14/3+c

c=3+14/3

c=23/3

Based on the above, the equation of the line we are looking for is:

y=-2/3x+23/3

Answer 2

Explanation:

Givens

Line: y = 3x + 3

Point: (7,3)

Discussion

The easiest variation on line problems is one like this one. The reason is that all you need do is read the slope of the given line.

m = 3 of the given line. Also the slope of the new line.

What you have so far is

y = 3x + b

The point is used to find b -- the y intercept.

x = 7

y = 3

You are not given this, but what you want to think is that when x = 7, y = 3

Substitute into the new equation

3 = 3*7 + b

3 = 21 + b Subtract 21 from both sides.

3 - 21 = 21-21 + b

- 18 = b

Answer

y = 3x - 18