Question

Is my graph correct?

And what is the range of the function above?

Answer 1

The range is f(x) <= 4.

Explanation:

The general form of a straight line is y = mx + c where m = the slope of the line and c = the y-intercept. If we compare this with y = 5x + 4 we see that the slope = 5 and the y-intercept is 4.

Your graph has got the wrong slope . The slope should be the coefficient of x which is 5. The slope of your graph ( rise / run) = 1. The y-intercept is +4 which you have correct.

Also since the domain is x <= 0 the line should stop

at the point (0, 4) because the maximum value of y is 4.

Answer 2

Graph is incorrect.

Find points (x,y)

If x=#, what does y=?

Example:

Y=5x+4

Y=5•0+4

Y=0+4

Y=4

Points:

(0,4)

(-1,1)

(-2,-6)

Also, only draw the line in areas where x≤0

Meaning nothing should be on the right half of the square.

The range means what Y values are possible?

When draw properly, with nothing on the right half, the highest Y value will be 4.

So, the range is y≤4