Question

Write an equation of the circle whose radius is 3 and whose center is (-1,6).

Answer 1

(x+1)^2 + (y-6)^2 = 3^2

Explanation:

The general equation for a circle is given by

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

Substituting in the point (-1,6) and the radius 3

(x--1)^2 + (y-6)^2 = 3^2

(x+1)^2 + (y-6)^2 = 3^2