2 Answers

Rachvela · Answer 1 · 2020-04-13T17:54:09+0000

Hello!

The answers are:

$x=-8\\y=0$

Since we have to equations, first we need to isolate one variable, and then substitute it into the other equation.

So, isolating x from the first equation we have:

$x-4y=-8\\x=-8+4y$

Then, substituting "x" into the second equation, we have:

$2(-8+4y)-3y=-16\\-16+8y-3y-=-16\\5y=-16+16\\5y=0\\y=(0)/(5)=0$

Therefore, substituting "y" into the first equation, we have:

$x-4(0)=-8\\x-0=-8\\x=-8$

So, the solutions for the system of equation are:

$x=-8\\y=0$

Have a nice day!

Brian Vo · Answer 2 · 2020-04-18T10:47:34+0000

Answer:
$x=-8\\y=0$

Explanation:

You can apply the elimination method:

- Multiply the first equation by -2.

- Add both equations to cancel out the variable x.

- Solve for y:

$\left \{ {{(-2)(x-4y)=-8(-2)} \atop {2x-3y=-16}} \right.\\\\\\\left \{ {{-2x+8y=16} \atop {2x-3y=-16}} \right.\\ ------\\5y=0\\y=0$

- Substitute y=0 into any of the original equations ans solve for x. Then:

$x-4(0)=-8\\x=-8$