Question

17........................

Answer 1

Explanation:

First, add 3 to both sides:

-5 = -6∛(x²)

Next, divide both sides by -6, to isolate ∛(x²):

5/6 = ∛(x²)

Eliminate the radical by cubing both sides:

5³

---- = x²

6³

Finally, take the square root of both sides. This will isolate x. There will be two roots: one +, the other -.

x = ±√(5³/6³)

This simplifies to: ± (5/6)∛(5/6).

Answer 2

a.
`0.76,-0.76`

Explanation:

The given equation is;

`-8=-3-6\sqrt[3]{x^2}`

Add 3 to both sides of the equation to get;

`-8+3=-3+3-6\sqrt[3]{x^2}`

`\Rightarrow -5=-6\sqrt[3]{x^2}`

Divide both sides by -6.

`\Rightarrow (-5)/(-6)=\sqrt[3]{x^2}`

`\Rightarrow (5)/(6)=\sqrt[3]{x^2}`

Cube both sides of the equation;

`\Rightarrow ((5)/(6))^3=x^2`

`\Rightarrow (125)/(216)=x^2`

Take square root of both sides

`\pm \sqrt{(125)/(216)}=x`

`\pm 0.76=x`

`\therefore x=0.76,-0.76`