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How many moles of H2SO4 are there in 0.035L of a 0.500 solution ?

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I am assuming you forgot to include the unit of molarity, M, at the end of 0.500.

Molarity's formula is M=moles solute/liters solution.

We are given molarity and liters so we can rearrange the equation to solve for moles solute. Therefore:

moles solute=molarity * liters solution

moles solute= 0.500M * 0.035L = 0.0175

Thus there are 0.0175 mols of H2SO4 in 0.035L of a 0.500M solution.

User Zbigniew Mazur
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