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Given 8y — 6x =8 :

A) transform the equation into slope-intercept form.

b) find the slope and y-intercept of the line.

c) what is the slope of a line parallel to this line?

d) what is the slope of a line perpendicular to this line ?

e) find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point (0,2).

1 Answer

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Answer:

Explanation:

A: slope-intercept form: Solve 8y — 6x =8 for y, as follows: 8y = 6x + 8, so that y = (3/4)x + 1.

B: Slope: 3/4; y-intercept: (0, 1)

C: Any line parallel to this line has the same slope, namely, 3/4.

D: Any line perpendicular to this line has a slope that is the negative reciprocal of 3/4; that is, the slope of the perp. line is -4/3.

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