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F(t)=3-2t.2t+t write in standard form

User NuzzeSicK
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1 Answer

3 votes

Hello!

The answer is:
f(t)=-4t^(2)+t+3

Why?

Since we are given a quadratic function, we need to write it using the standard form of quadratic function (parabola).

The given function is:


f(t)=3-2t.2t=+t

The standard form of a parabola is:


f(t)=a^(2)+bx+c

Where,

a is equal to the quadratic variable coefficient

b is equal to the linear variable coefficient

c is the constant number

So, writing the function in the standard form will be:


f(t)=3-2t*2t+t=3-4t^(2)+t=-4t^(2)+t+3


f(t)=-4t^(2)+t+3

Where,


a=-4\\b=1\\c=3

Have a nice day!

User Cold
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