Question

X intercept
Of v^2 +5v+6=0

Answer 1

x-intercepts:

x = -2 and x = -3 ⇒ (-2, 0) and (-3, 0).

Explanation:

`f(v)=v^2+5v+6\\\\\text{The x-intercept is for y = 0.}\\\\v^2+5v+6=0\\\\v^2+2v+3v+6=0\\\\v(v+2)+3(v+2)=0\\\\(v+2)(v+3)=0\iff v+2=0\ \vee\ v+3=0\\\\v+2=0\qquad\text{subtract 2 from both sides}\\v=-2\\\\v+3=0\qquad\text{subtract 3 from both sides}\\v=-3`