Question

Plz help !! Needed to graduate

Answer 1

the second one

Explanation:

Just put the equation in the quadratic formula but first get it in the ax^2+bx+c=0 form for that take 1 to the other side and subtract it

`8x^2-2x-1\\a=8,b=-2,c=-1`

the quadratic formula is shown in the picture along with the rest of the working

the answer is the second option :)

hope this helps, best of luck graduating :)

Answer 2

Answer:
`\bold{(2\pm √(36))/(16)}`

Explanation:

`8x^2-2x-1=0\quad \rightarrow \quad a=8,\ b=-2,\ c=-1\\\\\\Quadratic\ formula: x=(-b\pm √(b^2-4ac))/(2a)\\\\\\x=(-(-2)\pm √((-2)^2-4(8)(-1)))/(2(8))\\\\\\.\ =(2\pm √(4+32))/(16)\\\\\\.\ =(2\pm √(36))/(16)`