Question

An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow. During this acceleration, what was the net force on the arrow to the nearest newton?

Answer 1

300 N

Step-by-step explanation:

because it is

Answer 2

300 N

Step-by-step explanation:

The net force acting on the arrow is given by Newton's Second Law:

`F=ma`

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

`F=(0.06 kg)(5,000 m/s^2)=300 N`