Question

Tristan rode his bike 3 2/3 miles on Saturday he rode 1 4/5 Mi on Sunday how many more miles did he ride on Saturday then on Sunday a.1 3/15 Miles b.1 3/5 c.1 13/15 d.2 13/15​

Answer 1

c. 1 13/15

Explanation:

The best way to find out how much more Tristan rode his bike would be to subtract both of his distances together.

Saturday =
`3(2)/(3)`

Sunday =
`1(4)/(5)`

Now we actually have two different fractions with different denominators.

We can solve this first by converting the mixed numbers into improper fractions.

`3(2)/(3)=(9+2)/(3)`

`3(2)/(3)=(11)/(3)`

Now how did I do that?

First we take the denominator and multiply it to our whole number, then add the product to the numerator.

Let's proceed to the next mixed fraction.

`1(4)/(5)=(5+4)/(5)`

`1(4)/(5)=(9)/(5)`

We are then left with:

`(11)/(3)-(9)/(5)`

Since we cannot subtract them directly because they have different denominators, we need to find the LCD of both denominators.

`((5)/(5)) (11)/(3)-(9)/(5)((3)/(3))`

`(55)/(15)-(27)/(15)`

Now that they have similar denominators, we can then proceed to subtract them to each other.

`(55)/(15)-(27)/(15)=(28)/(15)or1(13)/(15)`