Question

Identify the area of the rhombus.

Answer 1

`A=240\ m^(2)`

Explanation:

we know that

A rhombus is a parallelogram with four congruent sides, the diagonals are perpendicular bisectors of each other

The area of a rhombus is equal to

`A=(1)/(2)(D1*D2)`

where

D1 and D2 are the diagonals

In this problem we have

`D1=16\ m`

Applying the Pythagoras Theorem find D2

`17^(2) =(D2/2)^(2)+(16/2)^(2)`

`(D2/2)^(2)=17^(2)-(16/2)^(2)`

`(D2/2)^(2)=225`

`(D2/2)=15`

`D2=30\ m`

Find the area of the rhombus

`A=(1)/(2)(16*30)=240\ m^(2)`