Identify the area of the rhombus.

Question

asked Mar 28, 2020 113k views

1 Answer

Brian Joseph Spinos · Answer 1 · 2020-04-01T02:55:43+0000

Answer:

$A=240\ m^(2)$

Explanation:

we know that

A rhombus is a parallelogram with four congruent sides, the diagonals are perpendicular bisectors of each other

The area of a rhombus is equal to

A=(1)/(2)(D1*D2)

where

D1 and D2 are the diagonals

In this problem we have

$D1=16\ m$

Applying the Pythagoras Theorem find D2

17^(2) =(D2/2)^(2)+(16/2)^(2)

(D2/2)^(2)=17^(2)-(16/2)^(2)

(D2/2)^(2)=225

(D2/2)=15

$D2=30\ m$

Find the area of the rhombus

$A=(1)/(2)(16*30)=240\ m^(2)$